What is the derivative of (ln(x))/2+2 ?

The derivative of (ln(x))/2+2 is 1/(2x)

What is the first derivative of (ln(x))/2+2 ?

The first derivative of (ln(x))/2+2 is 1/(2x)

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derivative of

\frac{ln ( x )}{2} + 2

\frac{1}{2 x}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{2} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{ln ( x )}{2}) + \frac{d}{d x} (2)

\frac{d}{d x} (\frac{ln ( x )}{2}) = \frac{1}{2 x}

\frac{d}{d x} (2) = 0

= \frac{1}{2 x} + 0

Simplify

= \frac{1}{2 x}

\frac{\partial}{\partial y} (1 + x ln (x y - 5))

\frac{d}{d x} (7 sin (2 x))

\frac{d}{d x} ((2 x + 3)^{5})

y = 3 x^{2} - 2 x - 2 e n x = 1

\int_{0}^{π} sin (t) e^{- s t} d t

What is the derivative of (ln(x))/2+2 ?
The derivative of (ln(x))/2+2 is 1/(2x)
What is the first derivative of (ln(x))/2+2 ?
The first derivative of (ln(x))/2+2 is 1/(2x)