What is the tangent of f(x)=-x^2+4x,\at x=3 ?

The tangent of f(x)=-x^2+4x,\at x=3 is y=-2x+9

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tangent of f(x)=-x^2+4x,\at x=3

tangent

y = - 2 x + 9

Solution steps

Find the tangent point:

(3, 3)

Find the slope of

f (x) = - x^{2} + 4 x : \frac{df ( x )}{d x} = - 2 x + 4

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(3, 3) : y = - 2 x + 9

y = - 2 x + 9

What is the tangent of f(x)=-x^2+4x,\at x=3 ?
The tangent of f(x)=-x^2+4x,\at x=3 is y=-2x+9