What is the derivative of sqrt(1+T^2) ?

The derivative of sqrt(1+T^2) is T/(sqrt(1+T^2))

What is the first derivative of sqrt(1+T^2) ?

The first derivative of sqrt(1+T^2) is T/(sqrt(1+T^2))

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derivative of

1 + T^{2}

\frac{T}{1 + T ^{2}}

Solution steps

\frac{d}{d T} (1 + T^{2})

Apply the chain rule:

\frac{1}{2 1 + T ^{2}} \frac{d}{d T} (1 + T^{2})

= \frac{1}{2 1 + T ^{2}} \frac{d}{d T} (1 + T^{2})

\frac{d}{d T} (1 + T^{2}) = 2 T

= \frac{1}{2 1 + T ^{2}} \cdot 2 T

Simplify

\frac{1}{2 1 + T ^{2}} \cdot 2 T : \frac{T}{1 + T ^{2}}

= \frac{T}{1 + T ^{2}}

\frac{d}{d x} (\frac{4 x - 3}{x ^{2} - 2 x})

f (x) = tan^{7} (x)

e^{x} + \frac{1}{1 + x}, 0

\int 19 tan^{3} (θ) d θ

\frac{\partial}{\partial y} (x^{5} - 6 x + 4 y^{3} - y^{2})

What is the derivative of sqrt(1+T^2) ?
The derivative of sqrt(1+T^2) is T/(sqrt(1+T^2))
What is the first derivative of sqrt(1+T^2) ?
The first derivative of sqrt(1+T^2) is T/(sqrt(1+T^2))