What is laplacetransform 5e^{-3(t-2)} ?

The answer to laplacetransform 5e^{-3(t-2)} is 5/(e^2(s+3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

laplacetransform 5e^{-3(t-2)}

laplace transform

5 e^{- 3 (t - 2)}

\frac{5}{e ^{2} ( s + 3 )}

Solution steps

L {5 e^{- 3 (t - 2)}}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 5 L {e^{- 3 t - 2}}

L {e^{- 3 t - 2}} : \frac{1}{e ^{2} ( s + 3 )}

= 5 \cdot \frac{1}{e ^{2} ( s + 3 )}

Refine

5 \frac{1}{e ^{2} ( s + 3 )} : \frac{5}{e ^{2} ( s + 3 )}

= \frac{5}{e ^{2} ( s + 3 )}

y^{^{''}} - 2 y^{^{'}} + y = 2 t - 1 - (6 t e^{t} + 6 e^{t})

1 + T^{2}

\frac{d}{d x} (\frac{4 x - 3}{x ^{2} - 2 x})

f (x) = tan^{7} (x)

e^{x} + \frac{1}{1 + x}, 0

What is laplacetransform 5e^{-3(t-2)} ?
The answer to laplacetransform 5e^{-3(t-2)} is 5/(e^2(s+3))