What is the derivative of e^{x^2-4x} ?

The derivative of e^{x^2-4x} is e^{x^2-4x}(2x-4)

What is the first derivative of e^{x^2-4x} ?

The first derivative of e^{x^2-4x} is e^{x^2-4x}(2x-4)

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derivative of

e^{x^{2} - 4 x}

e^{x^{2} - 4 x} (2 x - 4)

Solution steps

\frac{d}{d x} (e^{x^{2} - 4 x})

Apply the chain rule:

e^{x^{2} - 4 x} \frac{d}{d x} (x^{2} - 4 x)

= e^{x^{2} - 4 x} \frac{d}{d x} (x^{2} - 4 x)

\frac{d}{d x} (x^{2} - 4 x) = 2 x - 4

= e^{x^{2} - 4 x} (2 x - 4)

8 e^{4 x}

\frac{d}{d x} (tan (x) - sec (x))

\frac{\partial}{\partial x} (x^{3} + y^{3} - 9 x y)

x \to \frac{π}{4} lim (tan (x))

\frac{x}{x + 9}

What is the derivative of e^{x^2-4x} ?
The derivative of e^{x^2-4x} is e^{x^2-4x}(2x-4)
What is the first derivative of e^{x^2-4x} ?
The first derivative of e^{x^2-4x} is e^{x^2-4x}(2x-4)