What is the derivative of 8e^{4sqrt(x)} ?

The derivative of 8e^{4sqrt(x)} is (16e^{4sqrt(x)})/(sqrt(x))

What is the first derivative of 8e^{4sqrt(x)} ?

The first derivative of 8e^{4sqrt(x)} is (16e^{4sqrt(x)})/(sqrt(x))

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derivative of

8 e^{4 x}

\frac{16 e ^{4 x}}{x}

Solution steps

\frac{d}{d x} (8 e^{4 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 8 \frac{d}{d x} (e^{4 x})

Apply the chain rule:

e^{4 x} \frac{d}{d x} (4 x)

= e^{4 x} \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x) = \frac{2}{x}

= 8 e^{4 x} \frac{2}{x}

Simplify

8 e^{4 x} \frac{2}{x} : \frac{16 e ^{4 x}}{x}

= \frac{16 e ^{4 x}}{x}

\frac{d}{d x} (tan (x) - sec (x))

\frac{\partial}{\partial x} (x^{3} + y^{3} - 9 x y)

x \to \frac{π}{4} lim (tan (x))

\frac{x}{x + 9}

y = e^{- 4 t}, at t = 0

What is the derivative of 8e^{4sqrt(x)} ?
The derivative of 8e^{4sqrt(x)} is (16e^{4sqrt(x)})/(sqrt(x))
What is the first derivative of 8e^{4sqrt(x)} ?
The first derivative of 8e^{4sqrt(x)} is (16e^{4sqrt(x)})/(sqrt(x))