Solution
Solution
Solution steps
Solve Bernoulli ODE:
Graph
Popular Examples
Frequently Asked Questions (FAQ)
What is the solution for y^2=(xyy^'+1)ln(x) ?
The solution for y^2=(xyy^'+1)ln(x) is y=sqrt(2ln(x)+c_{1)ln^2(x)},y=-sqrt(2ln(x)+c_{1)ln^2(x)}