What is the derivative of 2cos(x+1) ?

The derivative of 2cos(x+1) is -2sin(x)

What is the first derivative of 2cos(x+1) ?

The first derivative of 2cos(x+1) is -2sin(x)

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\frac{d}{d x} (2 cos (x) + 1)

- 2 sin (x)

Solution steps

\frac{d}{d x} (2 cos (x) + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 cos (x)) + \frac{d}{d x} (1)

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

\frac{d}{d x} (1) = 0

= - 2 sin (x) + 0

Simplify

= - 2 sin (x)

\int \frac{sin ( 2 χ + 1 )}{( cos ( 2 χ + 1 ) ) ^{2}} d χ

\int_{2}^{10} \frac{1}{x - 1} d x

\int \frac{1}{16 + 4 x - 2 x ^{2}} d x

\int_{1}^{6} 2 π x (- \frac{3}{2} x + 9) d x

\frac{x + 1}{x + 2}

What is the derivative of 2cos(x+1) ?
The derivative of 2cos(x+1) is -2sin(x)
What is the first derivative of 2cos(x+1) ?
The first derivative of 2cos(x+1) is -2sin(x)