What is the integral from 2 to 10 of 1/(x-1) ?

The integral from 2 to 10 of 1/(x-1) is 2ln(3)

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integral from 2 to 10 of 1/(x-1)

\int_{2}^{10} \frac{1}{x - 1} d x

2 ln (3)

Decimal Notation

2.19722 \dots

Solution steps

\int_{2}^{10} \frac{1}{x - 1} d x

Apply u-substitution

: \int_{1}^{9} \frac{1}{u} d u

= \int_{1}^{9} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{9}

Compute the boundaries:

2 ln (3)

= 2 ln (3)

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\frac{x + 1}{x + 2}

\frac{d}{d x} (y - x^{2})

\int \frac{48 x}{4 x ^{2} + e} d x

What is the integral from 2 to 10 of 1/(x-1) ?
The integral from 2 to 10 of 1/(x-1) is 2ln(3)