xy^'+4y=8x^4,y(1)=2

Lösung

x y^{^{'}} + 4 y = 8 x^{4}, y (1) = 2

y = x^{4} + \frac{1}{x ^{4}}

Schritte zur Lösung

x y^{'} (x) + 4 y = 8 x^{4}

Solve linear ODE:

y = x^{4} + \frac{1}{x ^{4}}

y = x^{4} + \frac{1}{x ^{4}}

t an g e n t x^{2} + 3 x + 9, at x = 4

\frac{d}{d x} ((x + \frac{1}{x})^{2} - \frac{5}{3 x})

\frac{\partial}{\partial x} (x e^{3 y} sin (5 z))

n = 1 \sum \infty (\frac{5}{6})^{n}

d er i v a t i v e y = e^{k t a n (7 x)}