What is the derivative of f(x)= 1/5 x^2+(200000)/x ?

The derivative of f(x)= 1/5 x^2+(200000)/x is (2x)/5-(200000)/(x^2)

What is the first derivative of f(x)= 1/5 x^2+(200000)/x ?

The first derivative of f(x)= 1/5 x^2+(200000)/x is (2x)/5-(200000)/(x^2)

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derivative of

f (x) = \frac{1}{5} x^{2} + \frac{200000}{x}

\frac{2 x}{5} - \frac{200000}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{5} x^{2} + \frac{200000}{x})

Simplify

\frac{1}{5} x^{2} + \frac{200000}{x} : \frac{x ^{2}}{5} + \frac{200000}{x}

= \frac{d}{d x} (\frac{x ^{2}}{5} + \frac{200000}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{2}}{5}) + \frac{d}{d x} (\frac{200000}{x})

\frac{d}{d x} (\frac{x ^{2}}{5}) = \frac{2 x}{5}

\frac{d}{d x} (\frac{200000}{x}) = - \frac{200000}{x ^{2}}

= \frac{2 x}{5} - \frac{200000}{x ^{2}}

(1 + x^{2}) y^{^{''}} + y^{^{'}} x + a x = 0

f (t) = 3 cos (t)

\int \frac{sec ( x )}{2 sec ( x ) + 1} d x

x^{2} + y^{2} = 100, (- 6, 8)

\int - x cos (\frac{n x π}{l}) d x

What is the derivative of f(x)= 1/5 x^2+(200000)/x ?
The derivative of f(x)= 1/5 x^2+(200000)/x is (2x)/5-(200000)/(x^2)
What is the first derivative of f(x)= 1/5 x^2+(200000)/x ?
The first derivative of f(x)= 1/5 x^2+(200000)/x is (2x)/5-(200000)/(x^2)