What is (\partial)/(\partial x)(4x(2+y)^{-1}) ?

The answer to (\partial)/(\partial x)(4x(2+y)^{-1}) is 4/(2+y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(4x(2+y)^{-1})

\frac{\partial}{\partial x} (4 x (2 + y)^{- 1})

\frac{4}{2 + y}

Solution steps

\frac{\partial}{\partial x} (4 x (2 + y)^{- 1})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 (2 + y)^{- 1} \frac{\partial}{\partial x} (x)

Apply the common derivative:

\frac{\partial}{\partial x} (x) = 1

= 4 (2 + y)^{- 1} \cdot 1

Simplify

4 (2 + y)^{- 1} \cdot 1 : \frac{4}{2 + y}

= \frac{4}{2 + y}

f (x) = \frac{x}{1 + x ^{2}}, at x = 2

\int \frac{x}{x - 10} d x

9.86 x^{2}, 4.92 x - x^{2}

\frac{\partial}{\partial t} (t^{3})

5 - \frac{6}{x}

What is (\partial)/(\partial x)(4x(2+y)^{-1}) ?
The answer to (\partial)/(\partial x)(4x(2+y)^{-1}) is 4/(2+y)