What is the tangent of y=5-10x+x^3,\at x=-1 ?

The tangent of y=5-10x+x^3,\at x=-1 is y=-7x+7

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tangent of y=5-10x+x^3,\at x=-1

tangent of

y = 5 - 10 x + x^{3}, at x = - 1

y = - 7 x + 7

Solution steps

Find the tangent point:

(- 1, 14)

Find the slope of

y = 5 - 10 x + x^{3} : \frac{d y}{d x} = 3 x^{2} - 10

Compute the slope of

y = 5 - 10 x + x^{3}

x = - 1 : m = - 7

Find the line with slope m=

- 7

and passing through

(- 1, 14) : y = - 7 x + 7

y = - 7 x + 7

\frac{x}{1 + e ^{x}}

\int \frac{5 x ^{2} - 3}{x ^{3} - x} d x

f (x) = sin (π x^{2}) - π x, at x = 1

y = x^{3} - 8 x^{2} + 21 x + 2

y = \frac{90}{x ^{5}}

What is the tangent of y=5-10x+x^3,\at x=-1 ?
The tangent of y=5-10x+x^3,\at x=-1 is y=-7x+7