What is (\partial)/(\partial x)(4ycos(x)) ?

The answer to (\partial)/(\partial x)(4ycos(x)) is -4ysin(x)

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(\partial)/(\partial x)(4ycos(x))

\frac{\partial}{\partial x} (4 y cos (x))

- 4 y sin (x)

Solution steps

\frac{\partial}{\partial x} (4 y cos (x))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 y \frac{\partial}{\partial x} (cos (x))

Apply the common derivative:

\frac{\partial}{\partial x} (cos (x)) = - sin (x)

= 4 y (- sin (x))

Simplify

= - 4 y sin (x)

\frac{d x}{d t} = sin (3 t) cos (3 t)

x^{3} - 17 x^{2} + 63 x + 6

\frac{\partial}{\partial x} (x^{2} + y^{2} + 3 z)

\int (2 x) cos (x) d x

What is (\partial)/(\partial x)(4ycos(x)) ?
The answer to (\partial)/(\partial x)(4ycos(x)) is -4ysin(x)