What is (\partial)/(\partial x)(x^2+y^2+3z) ?

The answer to (\partial)/(\partial x)(x^2+y^2+3z) is 2x

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(\partial)/(\partial x)(x^2+y^2+3z)

\frac{\partial}{\partial x} (x^{2} + y^{2} + 3 z)

2 x

Solution steps

\frac{\partial}{\partial x} (x^{2} + y^{2} + 3 z)

Treat

y, z

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (3 z)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (3 z) = 0

= 2 x + 0 + 0

Simplify

= 2 x

\int (2 x) cos (x) d x

tan (x), 0, 1, 2, 3, \frac{π}{4}

y = 7 x, y = 6 x^{2}

x = 0, y = 2, y = x

What is (\partial)/(\partial x)(x^2+y^2+3z) ?
The answer to (\partial)/(\partial x)(x^2+y^2+3z) is 2x