What is the derivative of \sqrt[5]{7x} ?

The derivative of \sqrt[5]{7x} is (7^{1/5})/(5x^{4/5)}

What is the first derivative of \sqrt[5]{7x} ?

The first derivative of \sqrt[5]{7x} is (7^{1/5})/(5x^{4/5)}

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derivative of

\frac{7 ^{\frac{1}{5}}}{5 x ^{\frac{4}{5}}}

Solution steps

Apply the chain rule:

\frac{1}{5 ( 7 x ) ^{\frac{4}{5}}} \frac{d}{d x} (7 x)

= \frac{1}{5 ( 7 x ) ^{\frac{4}{5}}} \frac{d}{d x} (7 x)

\frac{d}{d x} (7 x) = 7

= \frac{1}{5 ( 7 x ) ^{\frac{4}{5}}} \cdot 7

Simplify

\frac{1}{5 ( 7 x ) ^{\frac{4}{5}}} \cdot 7 : \frac{7 ^{\frac{1}{5}}}{5 x ^{\frac{4}{5}}}

= \frac{7 ^{\frac{1}{5}}}{5 x ^{\frac{4}{5}}}

tan (x), 0, 1, 2, 3, \frac{π}{4}

y = 7 x, y = 6 x^{2}

x = 0, y = 2, y = x

(sin (t) - t cos (t))^{^{'}}

\frac{d}{d x} (\frac{4 x}{x + 5})

What is the derivative of \sqrt[5]{7x} ?
The derivative of \sqrt[5]{7x} is (7^{1/5})/(5x^{4/5)}
What is the first derivative of \sqrt[5]{7x} ?
The first derivative of \sqrt[5]{7x} is (7^{1/5})/(5x^{4/5)}