What is the tangent of f(x)=9x^2+6x-6 ?

The tangent of f(x)=9x^2+6x-6 is y=(18a_{0}+6)x-9a_{0}^2-6

Popular >

tangent of f(x)=9x^2+6x-6

tangent of

f (x) = 9 x^{2} + 6 x - 6

y = (18 a_{0} + 6) x - 9 a_{0}^{2} - 6

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 9 a_{0}^{2} + 6 a_{0} - 6)

Find the slope of

f (x) = 9 x^{2} + 6 x - 6 : \frac{df ( x )}{d x} = 18 x + 6

Compute the slope of

f (x) = 9 x^{2} + 6 x - 6

x = a_{0} : m = 18 a_{0} + 6

Find the line with slope m=

18 a_{0} + 6

and passing through

(a_{0}, 9 a_{0}^{2} + 6 a_{0} - 6) : y = (18 a_{0} + 6) x - 9 a_{0}^{2} - 6

y = (18 a_{0} + 6) x - 9 a_{0}^{2} - 6

7 π x^{2}

x \to 0 + lim (12 e^{- \frac{2}{x}})

f (R) = R^{3}

\int (1 + \frac{1}{x})^{- 3} \frac{1}{x ^{2}} d x

\int \frac{y ^{2}}{( y ^{2} + 3 ) ^{\frac{3}{2}}} d y

What is the tangent of f(x)=9x^2+6x-6 ?
The tangent of f(x)=9x^2+6x-6 is y=(18a_{0}+6)x-9a_{0}^2-6