What is the limit as x approaches 0+of 12e^{-2/x} ?

The limit as x approaches 0+of 12e^{-2/x} is 0

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limit as x approaches 0+of 12e^{-2/x}

x \to 0 + lim (12 e^{- \frac{2}{x}})

0

Solution steps

x \to 0 + lim (12 e^{- \frac{2}{x}})

x \to a lim [c \cdot f (x)] = c \cdot x \to a lim f (x)

= 12 \cdot x \to 0 + lim (e^{- \frac{2}{x}})

Apply the Limit Chain Rule:

0

= 12 \cdot 0

Simplify

= 0

f (R) = R^{3}

\int (1 + \frac{1}{x})^{- 3} \frac{1}{x ^{2}} d x

\int \frac{y ^{2}}{( y ^{2} + 3 ) ^{\frac{3}{2}}} d y

h \to 0 lim (\frac{sin ( 9 h )}{9 h})

x \to 0 lim (x + 9 - 3)

What is the limit as x approaches 0+of 12e^{-2/x} ?
The limit as x approaches 0+of 12e^{-2/x} is 0