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Popular >

derivative of (y^4)/8+1/(4y^2)

Solution

derivative of

\frac{y ^{4}}{8} + \frac{1}{4 y ^{2}}

Solution

\frac{y ^{3}}{2} - \frac{1}{2 y ^{3}}

Solution steps

\frac{d}{d y} (\frac{y ^{4}}{8} + \frac{1}{4 y ^{2}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{y ^{4}}{8}) + \frac{d}{d y} (\frac{1}{4 y ^{2}})

\frac{d}{d y} (\frac{y ^{4}}{8}) = \frac{y ^{3}}{2}

\frac{d}{d y} (\frac{1}{4 y ^{2}}) = - \frac{1}{2 y ^{3}}

= \frac{y ^{3}}{2} - \frac{1}{2 y ^{3}}

Popular Examples

5 y^{^{''}} + 26 y = 0

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sum from n=2 to infinity of 2nln(n)

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\frac{d}{d x} (\frac{x - 7}{x + 7})

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\int 9 x^{\frac{2}{3}} d x

Frequently Asked Questions (FAQ)

What is the derivative of (y^4)/8+1/(4y^2) ?
The derivative of (y^4)/8+1/(4y^2) is (y^3)/2-1/(2y^3)
What is the first derivative of (y^4)/8+1/(4y^2) ?
The first derivative of (y^4)/8+1/(4y^2) is (y^3)/2-1/(2y^3)