What is the solution for 5y^{''}+26y=0 ?

The solution for 5y^{''}+26y=0 is y=c_{1}cos(sqrt(26/5)t)+c_{2}sin(sqrt(26/5)t)

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5y^{''}+26y=0

5 y^{^{''}} + 26 y = 0

y = c_{1} cos (\frac{26}{5} t) + c_{2} sin (\frac{26}{5} t)

Solution steps

5 y^{''} (t) + 26 y = 0

Solve linear ODE:

y = c_{1} cos (\frac{26}{5} t) + c_{2} sin (\frac{26}{5} t)

y = c_{1} cos (\frac{26}{5} t) + c_{2} sin (\frac{26}{5} t)

e^{x^{2} + 9 x + 7}

n = 2 \sum \infty 2 n ln (n)

\frac{d}{d x} (\frac{x - 7}{x + 7})

\int 9 x^{\frac{2}{3}} d x

x \to - \infty lim (3 - 2^{x})

What is the solution for 5y^{''}+26y=0 ?
The solution for 5y^{''}+26y=0 is y=c_{1}cos(sqrt(26/5)t)+c_{2}sin(sqrt(26/5)t)