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Popular Calculus >

sum from n=2 to infinity of 2nln(n)

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Solution

n=2∑∞​2nln(n)

Solution

diverges
Solution steps
n=2∑∞​2nln(n)
Apply the constant multiplication rule: ∑c⋅an​=c⋅∑an​=2⋅n=2∑∞​nln(n)
Apply Series Divergence Test:diverges
=2diverges
=diverges

Popular Examples

integral of 9x^{2/3}limit as x approaches-infinity of 3-2^xderivative of ln(x/(x^2+c))integral from 0 to 8 of 2/(x^{2/3)}derivative of sqrt(5/x-1)

Frequently Asked Questions (FAQ)

  • What is the sum from n=2 to infinity of 2nln(n) ?

    The sum from n=2 to infinity of 2nln(n) is diverges
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