What is (\partial)/(\partial x)((1+x)sin(y)) ?

The answer to (\partial)/(\partial x)((1+x)sin(y)) is sin(y)

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(\partial)/(\partial x)((1+x)sin(y))

\frac{\partial}{\partial x} ((1 + x) sin (y))

sin (y)

Solution steps

\frac{\partial}{\partial x} ((1 + x) sin (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (y) \frac{\partial}{\partial x} (1 + x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= sin (y) (\frac{\partial}{\partial x} (1) + \frac{\partial}{\partial x} (x))

\frac{\partial}{\partial x} (1) = 0

\frac{\partial}{\partial x} (x) = 1

= sin (y) (0 + 1)

Simplify

= sin (y)

\frac{d}{d x} (ln (a x a + x))

\int \frac{1}{( x ^{2} - 49 ) ^{\frac{3}{2}}} d x

- y^{^{'}} + \frac{2 y}{x} = x^{3} y^{2}

t \to 0 lim (\frac{6}{1 + t})

f (x) = arcsin (x)

What is (\partial)/(\partial x)((1+x)sin(y)) ?
The answer to (\partial)/(\partial x)((1+x)sin(y)) is sin(y)