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Popular >

-y^'+(2y)/x =x^3y^2

Solution

- y^{^{'}} + \frac{2 y}{x} = x^{3} y^{2}

Solution

y = \frac{6 x ^{2}}{x ^{6} + c _{1}}

Solution steps

- y^{'} (x) + \frac{2 y}{x} = x^{3} y^{2}

Solve Bernoulli ODE:

y = \frac{6 x ^{2}}{x ^{6} + c _{1}}

y = \frac{6 x ^{2}}{x ^{6} + c _{1}}

Popular Examples

limit as t approaches 0 of 6/(1+t)

t \to 0 lim (\frac{6}{1 + t})

derivative of f(x)=arcsin(x)derivative of

f (x) = arcsin (x)

integral of sqrt(1+(2x)^2)

\int 1 + (2 x)^{2} d x

y^{''}+2y^'+y=12e-t

y^{^{''}} + 2 y^{^{'}} + y = 12 e - t

integral of csc^2(θ)-1

\int csc^{2} (θ) - 1 d θ

Frequently Asked Questions (FAQ)

What is the solution for -y^'+(2y)/x =x^3y^2 ?
The solution for -y^'+(2y)/x =x^3y^2 is y=(6x^2)/(x^6+c_{1)}