What is the integral from-infinity to 0 of 1/(5-4x) ?

The integral from-infinity to 0 of 1/(5-4x) is diverges

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integral from-infinity to 0 of 1/(5-4x)

\int_{- \infty}^{0} \frac{1}{5 - 4 x} d x

diverges

Solution steps

\int_{- \infty}^{0} \frac{1}{5 - 4 x} d x

Compute the indefinite integral:

\int \frac{1}{5 - 4 x} d x = - \frac{1}{4} ln ∣ 5 - 4 x ∣ + C

Compute the boundaries:

\int_{- \infty}^{0} \frac{1}{5 - 4 x} d x =

diverges

= diverges

\frac{d}{d x} (ln (13 x) + 13)

\frac{d y}{d x} = \frac{y ^{2} + 3 x x ^{2} + y ^{2}}{x y}

x \to 0 + lim (- csc^{2} (x))

\frac{d}{d x} (x^{2} (x + 3)^{10})

y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 3 x - 13

What is the integral from-infinity to 0 of 1/(5-4x) ?
The integral from-infinity to 0 of 1/(5-4x) is diverges