What is area y=x^3-2x^2+2,y=3x^2+3x-13 ?

The answer to area y=x^3-2x^2+2,y=3x^2+3x-13 is 30sqrt(3)+37/3

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area y=x^3-2x^2+2,y=3x^2+3x-13

area

y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 3 x - 13

303 + \frac{37}{3}

Decimal Notation

64.29485 \dots

Solution steps

Apply the area formula:

\int_{- 3}^{5} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 3 x - 13) d x

Solve

\int_{- 3}^{5} x^{3} - 2 x^{2} + 2 - (3 x^{2} + 3 x - 13) d x : 303 + \frac{37}{3}

The area is:

= 303 + \frac{37}{3}

\frac{d}{d x} f^{- 1} (x) = 2 x + ln (x + 1)

\int (1 - x)^{- 2} d x

\frac{\partial ^{2}}{\partial x \partial y} (x y^{2} - 6 x^{2} - 3 y^{2})

(7.4) (3.8)

x^{2} + 6 x - 1

What is area y=x^3-2x^2+2,y=3x^2+3x-13 ?
The answer to area y=x^3-2x^2+2,y=3x^2+3x-13 is 30sqrt(3)+37/3