What is (\partial ^2)/(\partial x\partial y)(xy^2-6x^2-3y^2) ?

The answer to (\partial ^2)/(\partial x\partial y)(xy^2-6x^2-3y^2) is 2y

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(\partial ^2)/(\partial x\partial y)(xy^2-6x^2-3y^2)

\frac{\partial ^{2}}{\partial x \partial y} (x y^{2} - 6 x^{2} - 3 y^{2})

2 y

Solution steps

\frac{\partial ^{2}}{\partial x \partial y} (x y^{2} - 6 x^{2} - 3 y^{2})

\frac{\partial}{\partial x} (x y^{2} - 6 x^{2} - 3 y^{2}) = y^{2} - 12 x

= \frac{\partial}{\partial y} (y^{2} - 12 x)

\frac{\partial}{\partial y} (y^{2} - 12 x) = 2 y

= 2 y

(7.4) (3.8)

x^{2} + 6 x - 1

\int - 2 x^{4} tan (x^{5}) d x

\frac{\partial}{\partial y} (4 x^{3} y^{2} + 2)

x^{2} y^{^{''}} + x y^{^{'}} - 9 y = x^{3} + 1

What is (\partial ^2)/(\partial x\partial y)(xy^2-6x^2-3y^2) ?
The answer to (\partial ^2)/(\partial x\partial y)(xy^2-6x^2-3y^2) is 2y