What is the derivative of ln(13x+13) ?

The derivative of ln(13x+13) is 1/x

What is the first derivative of ln(13x+13) ?

The first derivative of ln(13x+13) is 1/x

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\frac{d}{d x} (ln (13 x) + 13)

\frac{1}{x}

Solution steps

\frac{d}{d x} (ln (13 x) + 13)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (ln (13 x)) + \frac{d}{d x} (13)

\frac{d}{d x} (ln (13 x)) = \frac{1}{x}

\frac{d}{d x} (13) = 0

= \frac{1}{x} + 0

Simplify

= \frac{1}{x}

\frac{d y}{d x} = \frac{y ^{2} + 3 x x ^{2} + y ^{2}}{x y}

x \to 0 + lim (- csc^{2} (x))

\frac{d}{d x} (x^{2} (x + 3)^{10})

y = x^{3} - 2 x^{2} + 2, y = 3 x^{2} + 3 x - 13

\frac{d}{d x} f^{- 1} (x) = 2 x + ln (x + 1)

What is the derivative of ln(13x+13) ?
The derivative of ln(13x+13) is 1/x
What is the first derivative of ln(13x+13) ?
The first derivative of ln(13x+13) is 1/x