What is the integral of 22e^x ?

The integral of 22e^x is 22e^x+C

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integral of 22e^x

\int 22 e^{x} d x

22 e^{x} + C

Solution steps

\int 22 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 22 \cdot \int e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 22 e^{x}

Add a constant to the solution

= 22 e^{x} + C

\int \frac{e ^{x^{2}} - 1}{x} d x

\frac{d}{d x} (a (2 e^{- x} x - e^{- x} x^{2}))

x \to 1 lim (9 x - 5)

\frac{d}{d x} (x^{3} + x^{2} - 6 x)

h (x) = 2 x (6 x - 18)^{6}