What is the derivative of x^3+x^2-6x ?

The derivative of x^3+x^2-6x is 3x^2+2x-6

What is the first derivative of x^3+x^2-6x ?

The first derivative of x^3+x^2-6x is 3x^2+2x-6

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\frac{d}{d x} (x^{3} + x^{2} - 6 x)

3 x^{2} + 2 x - 6

Solution steps

\frac{d}{d x} (x^{3} + x^{2} - 6 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (6 x)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (6 x) = 6

= 3 x^{2} + 2 x - 6

h (x) = 2 x (6 x - 18)^{6}

\int \frac{7 - 4 x ^{3} + 6 x ^{6}}{x ^{6}} d x

3 y^{^{''}} - 8 y^{^{'}} - 3 y = 0, y (0) = - 9, y^{^{'}} (0) = 8

\int_{1}^{3} (\frac{3 x ^{2} - 7}{x ^{3}}) d x

\int t^{3} (7 + t^{4})^{3} d t

What is the derivative of x^3+x^2-6x ?
The derivative of x^3+x^2-6x is 3x^2+2x-6
What is the first derivative of x^3+x^2-6x ?
The first derivative of x^3+x^2-6x is 3x^2+2x-6