What is the limit as x approaches 1 of sqrt(9x-5) ?

The limit as x approaches 1 of sqrt(9x-5) is 2

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limit as x approaches 1 of sqrt(9x-5)

x \to 1 lim (9 x - 5)

2

Solution steps

x \to 1 lim (9 x - 5)

Plug in the value

x = 1

= 9 \cdot 1 - 5

Simplify

9 \cdot 1 - 5 : 2

= 2

\frac{d}{d x} (x^{3} + x^{2} - 6 x)

h (x) = 2 x (6 x - 18)^{6}

\int \frac{7 - 4 x ^{3} + 6 x ^{6}}{x ^{6}} d x

3 y^{^{''}} - 8 y^{^{'}} - 3 y = 0, y (0) = - 9, y^{^{'}} (0) = 8

\int_{1}^{3} (\frac{3 x ^{2} - 7}{x ^{3}}) d x

What is the limit as x approaches 1 of sqrt(9x-5) ?
The limit as x approaches 1 of sqrt(9x-5) is 2