What is the derivative of f(x)=x^2-x ?

The derivative of f(x)=x^2-x is 2x-1

What is the first derivative of f(x)=x^2-x ?

The first derivative of f(x)=x^2-x is 2x-1

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derivative of

f (x) = x^{2} - x

2 x - 1

Solution steps

\frac{d}{d x} (x^{2} - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d x}{d x}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d x}{d x} = 1

= 2 x - 1

\frac{d}{d s} (4^{- 3} (\frac{2}{s ^{7}} + 3 s)^{4})

\int x^{3} ln ∣ 1 + x ∣ d x

x \to - 1 lim (\frac{x - 3}{x + 1})

f (x) = \frac{x ^{3} + 2 x ^{2} + 3 x + 4}{x}

\frac{d}{d x} (9 - x)

What is the derivative of f(x)=x^2-x ?
The derivative of f(x)=x^2-x is 2x-1
What is the first derivative of f(x)=x^2-x ?
The first derivative of f(x)=x^2-x is 2x-1