What is the first derivative of 9-x ?

The first derivative of 9-x is -1

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derivative of 9-x

\frac{d}{d x} (9 - x)

- 1

Solution steps

\frac{d}{d x} (9 - x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (9) - \frac{d x}{d x}

\frac{d}{d x} (9) = 0

\frac{d x}{d x} = 1

= 0 - 1

Simplify

= - 1

4 π x^{2}

n = 1 \sum \infty \frac{1}{n ^{2} + 2 n}

\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{s - 2}

f (x) = (1 - x) (x^{2} - 3)^{2}

n = 0 \sum \infty 1^{2 n}