What is the limit as x approaches-1 of (x-3)/(x+1) ?

The limit as x approaches-1 of (x-3)/(x+1) is diverges

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limit as x approaches-1 of (x-3)/(x+1)

x \to - 1 lim (\frac{x - 3}{x + 1})

diverges

Solution steps

x \to - 1 lim (\frac{x - 3}{x + 1})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x - 3}{x + 1}) = - \infty

x \to - 1 - lim (\frac{x - 3}{x + 1}) = \infty

= diverges

f (x) = \frac{x ^{3} + 2 x ^{2} + 3 x + 4}{x}

\frac{d}{d x} (9 - x)

4 π x^{2}

n = 1 \sum \infty \frac{1}{n ^{2} + 2 n}

\frac{1}{s ^{2}} - \frac{1}{s} + \frac{1}{s - 2}

What is the limit as x approaches-1 of (x-3)/(x+1) ?
The limit as x approaches-1 of (x-3)/(x+1) is diverges