What is the solution for (dy)/(dx)=sin(x-y) ?

The solution for (dy)/(dx)=sin(x-y) is y=-pi/2-2pin+x,y=-2arctan((-2+c_{1}+x)/(c_{1)+x})-2pin+x

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=sin(x-y)

\frac{d y}{d x} = sin (x - y)

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x

Solution steps

\frac{d y}{d x} = sin (x - y)

Solve using substitution:

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x

y = - \frac{π}{2} - 2 πn + x, y = - 2 arctan (\frac{- 2 + c _{1} + x}{c _{1} + x}) - 2 πn + x

\int sin (x) cos (x) 2 - cos^{2} (x) d x

\int (e^{s} - e^{- s})^{2} d s

\frac{5 - x ^{2}}{( 5 + x ^{2} ) ^{2}}

\frac{d}{d x} (3 x^{\frac{3}{2}} - 1)

\int \frac{36}{x ^{3}} d x

What is the solution for (dy)/(dx)=sin(x-y) ?
The solution for (dy)/(dx)=sin(x-y) is y=-pi/2-2pin+x,y=-2arctan((-2+c_{1}+x)/(c_{1)+x})-2pin+x