What is the derivative of 3x^{3/2}-1 ?

The derivative of 3x^{3/2}-1 is (9x^{1/2})/2

What is the first derivative of 3x^{3/2}-1 ?

The first derivative of 3x^{3/2}-1 is (9x^{1/2})/2

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\frac{d}{d x} (3 x^{\frac{3}{2}} - 1)

\frac{9 x ^{\frac{1}{2}}}{2}

Solution steps

\frac{d}{d x} (3 x^{\frac{3}{2}} - 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{\frac{3}{2}}) - \frac{d}{d x} (1)

\frac{d}{d x} (3 x^{\frac{3}{2}}) = \frac{9 x ^{\frac{1}{2}}}{2}

\frac{d}{d x} (1) = 0

= \frac{9 x ^{\frac{1}{2}}}{2} - 0

Simplify

= \frac{9 x ^{\frac{1}{2}}}{2}

\int \frac{36}{x ^{3}} d x

x \to 1 lim (9)

\int sin (5 x) cos (7 x) d x

\frac{5}{x}, \frac{5}{x ^{2}}, 1, 4

y = - 3 x + 2, x = 2

What is the derivative of 3x^{3/2}-1 ?
The derivative of 3x^{3/2}-1 is (9x^{1/2})/2
What is the first derivative of 3x^{3/2}-1 ?
The first derivative of 3x^{3/2}-1 is (9x^{1/2})/2