What is the integral of (36)/(x^3) ?

The integral of (36)/(x^3) is -(18)/(x^2)+C

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integral of (36)/(x^3)

\int \frac{36}{x ^{3}} d x

- \frac{18}{x ^{2}} + C

Solution steps

\int \frac{36}{x ^{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 36 \cdot \int \frac{1}{x ^{3}} d x

Apply the Power Rule

: - \frac{1}{2 x ^{2}}

= 36 (- \frac{1}{2 x ^{2}})

Simplify

36 (- \frac{1}{2 x ^{2}}) : - \frac{18}{x ^{2}}

= - \frac{18}{x ^{2}}

Add a constant to the solution

= - \frac{18}{x ^{2}} + C

x \to 1 lim (9)

\int sin (5 x) cos (7 x) d x

\frac{5}{x}, \frac{5}{x ^{2}}, 1, 4

y = - 3 x + 2, x = 2

\int (\frac{x + 9}{x}) d x

What is the integral of (36)/(x^3) ?
The integral of (36)/(x^3) is -(18)/(x^2)+C