What is the solution for (y+x^3+xy^2)dx-xdy=0 ?

The solution for (y+x^3+xy^2)dx-xdy=0 is y=tan((x^2)/2+c_{1})x

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(y+x^3+xy^2)dx-xdy=0

(y + x^{3} + x y^{2}) d x - x d y = 0

y = tan (\frac{x ^{2}}{2} + c_{1}) x

Solution steps

(y + x^{3} + x y^{2}) d x - x d y = 0

Solve using substitution:

y = tan (\frac{x ^{2}}{2} + c_{1}) x

y = tan (\frac{x ^{2}}{2} + c_{1}) x

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What is the solution for (y+x^3+xy^2)dx-xdy=0 ?
The solution for (y+x^3+xy^2)dx-xdy=0 is y=tan((x^2)/2+c_{1})x