What is the integral of e^{1-x}x ?

The integral of e^{1-x}x is -e^{1-x}x-e^{1-x}+C

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integral of e^{1-x}x

\int e^{1 - x} x d x

- e^{1 - x} x - e^{1 - x} + C

Solution steps

\int e^{1 - x} x d x

Apply Integration By Parts

: - e^{1 - x} x - \int - e^{1 - x} d x

= - e^{1 - x} x - \int - e^{1 - x} d x

\int - e^{1 - x} d x = e^{1 - x}

= - e^{1 - x} x - e^{1 - x}

Add a constant to the solution

= - e^{1 - x} x - e^{1 - x} + C

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\frac{\partial}{\partial x} (\frac{1}{x})

What is the integral of e^{1-x}x ?
The integral of e^{1-x}x is -e^{1-x}x-e^{1-x}+C