What is (\partial)/(\partial x)(2x^2+y) ?

The answer to (\partial)/(\partial x)(2x^2+y) is 4x

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(\partial)/(\partial x)(2x^2+y)

\frac{\partial}{\partial x} (2 x^{2} + y)

4 x

Solution steps

\frac{\partial}{\partial x} (2 x^{2} + y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (2 x^{2}) + \frac{\partial}{\partial x} (y)

\frac{\partial}{\partial x} (2 x^{2}) = 4 x

\frac{\partial}{\partial x} (y) = 0

= 4 x + 0

Simplify

= 4 x

\frac{\partial}{\partial x} (\frac{1}{x})

\frac{d}{d x} (\frac{sin ^{2} ( x )}{x ^{2}})

\frac{d}{d x} (3^{3 x})

\frac{\partial}{\partial x} (2 e^{x^{9} y})

(\frac{x + 9}{x - 9})^{5}

What is (\partial)/(\partial x)(2x^2+y) ?
The answer to (\partial)/(\partial x)(2x^2+y) is 4x