What is the derivative of 3^{3x} ?

The derivative of 3^{3x} is ln(3)*3^{3x+1}

What is the first derivative of 3^{3x} ?

The first derivative of 3^{3x} is ln(3)*3^{3x+1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (3^{3 x})

ln (3) \cdot 3^{3 x + 1}

Solution steps

\frac{d}{d x} (3^{3 x})

Simplify

3^{3 x} : 2 7^{x}

= \frac{d}{d x} (2 7^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 2 7^{x} ln (27)

Simplify

2 7^{x} ln (27) : ln (3) \cdot 3^{3 x + 1}

= ln (3) \cdot 3^{3 x + 1}

\frac{\partial}{\partial x} (2 e^{x^{9} y})

(\frac{x + 9}{x - 9})^{5}

x \to 16 lim (\frac{( 4 - x )}{( 16 x - x ^{2} )})

\int (1 - t^{- 0.52}) d t

y^{^{'}} = y - 1

What is the derivative of 3^{3x} ?
The derivative of 3^{3x} is ln(3)*3^{3x+1}
What is the first derivative of 3^{3x} ?
The first derivative of 3^{3x} is ln(3)*3^{3x+1}