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Popular >

y^'=x(x-1)

Solution

y^{^{'}} = x (x - 1)

Solution

y = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

Solution steps

y^{'} (x) = x (x - 1)

If

f^{^{'}} (x) = g (x)

then

f (x) = \int g (x) d x

y = \int x (x - 1) d x

\int x (x - 1) d x = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

y = \frac{x ^{3}}{3} - \frac{x ^{2}}{2} + c_{1}

Popular Examples

(y+x^3+xy^2)dx-xdy=0

(y + x^{3} + x y^{2}) d x - x d y = 0

integral of e^{1-x}x

\int e^{1 - x} x d x

integral of (x-1)sqrt(x)

\int (x - 1) x d x

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\frac{\partial}{\partial x} (x^{2} sin (4 t))

integral of x/(sqrt(3x+4))

\int \frac{x}{3 x + 4} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'=x(x-1) ?
The solution for y^'=x(x-1) is y=(x^3)/3-(x^2)/2+c_{1}