What is the integral from 6 to 10 of 1/((x-6)^4) ?

The integral from 6 to 10 of 1/((x-6)^4) is diverges

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integral from 6 to 10 of 1/((x-6)^4)

\int_{6}^{10} \frac{1}{( x - 6 ) ^{4}} d x

diverges

Solution steps

\int_{6}^{10} \frac{1}{( x - 6 ) ^{4}} d x

Apply u-substitution

: \int_{0}^{4} \frac{1}{u ^{4}} d u

= \int_{0}^{4} \frac{1}{u ^{4}} d u

Apply the Power Rule

: [- \frac{1}{3 u ^{3}}]_{0}^{4}

= [- \frac{1}{3 u ^{3}}]_{0}^{4}

Compute the boundaries:

diverges

= diverges

\int \frac{x}{2 x + 4} d x

x \to 3 lim (\frac{12 - x - 3}{1 + x - x ^{2} + 7})

\frac{d}{d y} (- 2 x y sin (x^{2} y))

\int \frac{1}{sin ^{2} ( θ )} d θ

\int \frac{1}{12 x + 0.02 x ^{2}} d x

What is the integral from 6 to 10 of 1/((x-6)^4) ?
The integral from 6 to 10 of 1/((x-6)^4) is diverges