What is the integral of 1/(sin^2(θ)) ?

The integral of 1/(sin^2(θ)) is -cot(θ)+C

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integral of 1/(sin^2(θ))

\int \frac{1}{sin ^{2} ( θ )} d θ

- cot (θ) + C

Solution steps

\int \frac{1}{sin ^{2} ( θ )} d θ

Use the common integral:

\int \frac{1}{sin ^{2} ( θ )} d θ = - cot (θ)

= - cot (θ)

Add a constant to the solution

= - cot (θ) + C

\int \frac{1}{12 x + 0.02 x ^{2}} d x

\frac{d}{d x} (sin (ln ((x^{2} + 4)^{4})))

7 x - 8 y x^{2} + 1 \frac{d y}{d x} = 0

\int \frac{2 x + 2}{x ^{2} - 2 x + 1} d x

x \to 8 lim (\frac{x ^{2} - 5}{x - 8})

What is the integral of 1/(sin^2(θ)) ?
The integral of 1/(sin^2(θ)) is -cot(θ)+C