x^2+12x-28=0

解

x^{2} + 12 x - 28 = 0

x = 2, x = - 14

解答ステップ

x^{2} + 12 x - 28 = 0

解くとthe二次式

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot ( - 28 )}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot (- 28) = 16

x_{1, 2} = \frac{- 12 \pm 16}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 12 + 16}{2 \cdot 1}, x_{2} = \frac{- 12 - 16}{2 \cdot 1}

x = \frac{- 12 + 16}{2 \cdot 1} : 2

x = \frac{- 12 - 16}{2 \cdot 1} : - 14

二次equationの解:

x = 2, x = - 14