What are the solutions to the equation (x-2)^2-4(x-2)-21=0 ?

The solutions to the equation (x-2)^2-4(x-2)-21=0 are x=9,x=-1

Find the zeros of (x-2)^2-4(x-2)-21=0

The zeros of (x-2)^2-4(x-2)-21=0 are x=9,x=-1

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(x - 2)^{2} - 4 (x - 2) - 21 = 0

x = 9, x = - 1

Solution steps

(x - 2)^{2} - 4 (x - 2) - 21 = 0

Expand

(x - 2)^{2} - 4 (x - 2) - 21 : x^{2} - 8 x - 9

x^{2} - 8 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 9) = 10

x_{1, 2} = \frac{- ( - 8 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 10}{2 \cdot 1}

x = \frac{- ( - 8 ) + 10}{2 \cdot 1} : 9

x = \frac{- ( - 8 ) - 10}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 9, x = - 1

2^{\frac{1}{2}} \cdot 2^{\frac{1}{2}}

85 = 175 x - 16 x^{2}

x^{3} - 6 x^{2} + 2 x - 12

2 k^{2} + k - 6 = 0

\frac{2}{7} - \frac{3}{2 b}

What are the solutions to the equation (x-2)^2-4(x-2)-21=0 ?
The solutions to the equation (x-2)^2-4(x-2)-21=0 are x=9,x=-1
Find the zeros of (x-2)^2-4(x-2)-21=0
The zeros of (x-2)^2-4(x-2)-21=0 are x=9,x=-1