What are the solutions to the equation 85=175x-16x^2 ?

The solutions to the equation 85=175x-16x^2 are x=(175-sqrt(25185))/(32),x=(175+sqrt(25185))/(32)

Find the zeros of 85=175x-16x^2

The zeros of 85=175x-16x^2 are x=(175-sqrt(25185))/(32),x=(175+sqrt(25185))/(32)

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85 = 175 x - 16 x^{2}

x = \frac{175 - 25185}{32}, x = \frac{175 + 25185}{32}

Decimal Notation

x = 0.50944 \dots, x = 10.42805 \dots

Solution steps

85 = 175 x - 16 x^{2}

Switch sides

175 x - 16 x^{2} = 85

Move

85

to the left side

175 x - 16 x^{2} - 85 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 16 x^{2} + 175 x - 85 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 175 \pm 17 5 ^{2} - 4 ( - 16 ) ( - 85 )}{2 ( - 16 )}

17 5^{2} - 4 (- 16) (- 85) = 25185

x_{1, 2} = \frac{- 175 \pm 25185}{2 ( - 16 )}

Separate the solutions

x_{1} = \frac{- 175 + 25185}{2 ( - 16 )}, x_{2} = \frac{- 175 - 25185}{2 ( - 16 )}

x = \frac{- 175 + 25185}{2 ( - 16 )} : \frac{175 - 25185}{32}

x = \frac{- 175 - 25185}{2 ( - 16 )} : \frac{175 + 25185}{32}

The solutions to the quadratic equation are:

x = \frac{175 - 25185}{32}, x = \frac{175 + 25185}{32}

x^{3} - 6 x^{2} + 2 x - 12

2 k^{2} + k - 6 = 0

\frac{2}{7} - \frac{3}{2 b}

x^{2} - 3.2 x + 2.56 - 0.0909090909 = 0

5 x^{2} + 8 x \leq 4

What are the solutions to the equation 85=175x-16x^2 ?
The solutions to the equation 85=175x-16x^2 are x=(175-sqrt(25185))/(32),x=(175+sqrt(25185))/(32)
Find the zeros of 85=175x-16x^2
The zeros of 85=175x-16x^2 are x=(175-sqrt(25185))/(32),x=(175+sqrt(25185))/(32)