en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5x^2+8x<= 4

Solution

5 x^{2} + 8 x \leq 4

Solution

- 2 \leq x \leq \frac{2}{5}

+2

Interval Notation

[- 2, \frac{2}{5}]

Decimal Notation

- 2 \leq x \leq 0.4

Solution steps

5 x^{2} + 8 x \leq 4

Rewrite in standard form

5 x^{2} + 8 x - 4 \leq 0

Factor

5 x^{2} + 8 x - 4 : (5 x - 2) (x + 2)

(5 x - 2) (x + 2) \leq 0

Identify the intervals

- 2 \leq x \leq \frac{2}{5}

Popular Examples

simplify (9x^{10}y^3)(-x^5y^3)simplify

(9 x^{10} y^{3}) (- x^{5} y^{3})

- 3 x - 4 > 2

x^{2} + 8 x + 3 = 0

simplify (12^{-2})/((-13)^0)simplify

\frac{1 2 ^{- 2}}{( - 13 ) ^{0}}

(f+3)/(12)= 7/2

\frac{f + 3}{12} = \frac{7}{2}

Frequently Asked Questions (FAQ)

What is 5x^2+8x<= 4 ?
The solution to 5x^2+8x<= 4 is -2<= x<= 2/5