What are the solutions to the equation x^2+8x+3=0 ?

The solutions to the equation x^2+8x+3=0 are x=-4+sqrt(13),x=-4-sqrt(13)

Find the zeros of x^2+8x+3=0

The zeros of x^2+8x+3=0 are x=-4+sqrt(13),x=-4-sqrt(13)

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x^{2} + 8 x + 3 = 0

x = - 4 + 13, x = - 4 - 13

Decimal Notation

x = - 0.39444 \dots, x = - 7.60555 \dots

Solution steps

x^{2} + 8 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 3 = 213

x_{1, 2} = \frac{- 8 \pm 2 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 13}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 13}{2 \cdot 1}

x = \frac{- 8 + 2 13}{2 \cdot 1} : - 4 + 13

x = \frac{- 8 - 2 13}{2 \cdot 1} : - 4 - 13

The solutions to the quadratic equation are:

x = - 4 + 13, x = - 4 - 13

\frac{1 2 ^{- 2}}{( - 13 ) ^{0}}

\frac{f + 3}{12} = \frac{7}{2}

\frac{1}{4} \cdot π

\frac{x ^{5}}{x ^{4}} \cdot x

0 = x^{2} - x - 6

What are the solutions to the equation x^2+8x+3=0 ?
The solutions to the equation x^2+8x+3=0 are x=-4+sqrt(13),x=-4-sqrt(13)
Find the zeros of x^2+8x+3=0
The zeros of x^2+8x+3=0 are x=-4+sqrt(13),x=-4-sqrt(13)