What are the solutions to the equation 0=x^2-x-6 ?

The solutions to the equation 0=x^2-x-6 are x=3,x=-2

Find the zeros of 0=x^2-x-6

The zeros of 0=x^2-x-6 are x=3,x=-2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0 = x^{2} - x - 6

x = 3, x = - 2

Solution steps

0 = x^{2} - x - 6

Switch sides

x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 6) = 5

x_{1, 2} = \frac{- ( - 1 ) \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 5}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 5}{2 \cdot 1}

x = \frac{- ( - 1 ) + 5}{2 \cdot 1} : 3

x = \frac{- ( - 1 ) - 5}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

a^{2} - a - 12

4 x^{2} + 2 x - 2 = 0

6

(n + \frac{1}{2} - 1) \frac{1}{2} + 0

\frac{1}{3} x + \frac{1}{2} = - 3 (\frac{3}{4} x - 5)

What are the solutions to the equation 0=x^2-x-6 ?
The solutions to the equation 0=x^2-x-6 are x=3,x=-2
Find the zeros of 0=x^2-x-6
The zeros of 0=x^2-x-6 are x=3,x=-2