What are the solutions to the equation 4x^2+2x-2=0 ?

The solutions to the equation 4x^2+2x-2=0 are x= 1/2 ,x=-1

Find the zeros of 4x^2+2x-2=0

The zeros of 4x^2+2x-2=0 are x= 1/2 ,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 2 x - 2 = 0

x = \frac{1}{2}, x = - 1

Decimal Notation

x = 0.5, x = - 1

Solution steps

4 x^{2} + 2 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

2^{2} - 4 \cdot 4 (- 2) = 6

x_{1, 2} = \frac{- 2 \pm 6}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 2 + 6}{2 \cdot 4}, x_{2} = \frac{- 2 - 6}{2 \cdot 4}

x = \frac{- 2 + 6}{2 \cdot 4} : \frac{1}{2}

x = \frac{- 2 - 6}{2 \cdot 4} : - 1

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 1

6

(n + \frac{1}{2} - 1) \frac{1}{2} + 0

\frac{1}{3} x + \frac{1}{2} = - 3 (\frac{3}{4} x - 5)

(x - 4)^{2} = 17

(2 5^{\frac{3}{4}})^{2}

What are the solutions to the equation 4x^2+2x-2=0 ?
The solutions to the equation 4x^2+2x-2=0 are x= 1/2 ,x=-1
Find the zeros of 4x^2+2x-2=0
The zeros of 4x^2+2x-2=0 are x= 1/2 ,x=-1